ashleypineda0506 ashleypineda0506
  • 09-12-2019
  • Chemistry
contestada

What is the temperature difference if 300 cal are used to warm water

Respuesta :

kalyani62 kalyani62
  • 16-12-2019

Answer:

The temperature difference is [tex]\frac{300}{m} Kkg^{-1}[/tex]

Explanation:

The formula that is to used is :

Δ[tex]Q=ms[/tex]Δ[tex]T[/tex]

where ,

  • Δ[tex]Q[/tex] is the heat supplied in calories = 300cal
  • [tex]m[/tex] is the mass of water taken = m (assumed)
  • Δ[tex]T[/tex] is the change in temperature
  • [tex]s[/tex] is the specific heat of water = [tex]1calK^{-1}Kg^{-1}[/tex]

ΔT :

[tex]\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}[/tex]

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