Answer:
1) x = 9, 3
2)[tex]x = 0, 3+\sqrt{3} , 3+\sqrt{3}[/tex]
Step-by-step explanation:
1) [tex]x^2-12x=-27\\x^2-12x+27 = 0\\[/tex]
After factoring:
[tex](x-9)(x-3) = 0\\x = 9, 3[/tex]
2) [tex]x^3-6x^2+6x=0\\x(x^2-6x+6)=0\\x(x-3-\sqrt{3})(x-3+\sqrt{3})[/tex]
[tex]x = 0, 3+\sqrt{3} , 3+\sqrt{3}[/tex]
