Answer:15
Step-by-step explanation:
(a^(2)+a^(-1))^(6)
=
(a^(2)+a^(-1))(a^(2)+a^(-1))(a^(2)+a^(-1))(a^(2)+a^(-1))(a^(2)+a^(-1))(a^(2)+a^(-1))
Applying pascal's triangle ad expanding
15+((1)/(a^(6)))+((6)/(a^(3)))+20a^(3)+15a^(6)+6a^(9)+a^(12)
15x^0 =15 ,since 15 is the number in front of the variable x^0
