tanodmuhammad2088 tanodmuhammad2088
  • 09-10-2019
  • Physics
contestada

What is the % error in using g = 10.0 m/s^2? (Take the value ofg as 9.8 m/s^2)

Respuesta :

aristeus aristeus
  • 10-10-2019

Answer:

So percentage error will be 2 %

Explanation:

We have given initial value of acceleration due to gravity [tex]g=10m/sec^2[/tex]

And final value of acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

We have to find the percentage error

We know that percentage error is given by [tex]percentage\ error=\frac{initial\ value-final\ value}{initial\ value}\times 100[/tex]

So [tex]percentage\ error=\frac{10-9.8}{10}\times 100=2[/tex] %

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