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  • 09-10-2019
  • Mathematics
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Question no

1.11

1.12 only

Question no 111 112 only class=

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Аноним Аноним
  • 09-10-2019

1.11

Let x be the number of employees in 2011. The number of employees in 2012 was 105% of x, i.e.

[tex]x\cdot \dfrac{105}{100}[/tex]

The number of employees in 2013 was 105% of the number of employees in 2012, i.e.

[tex]\left(x\cdot \dfrac{105}{100}\right)\cdot \dfrac{105}{100}\right = x\cdot \left(\dfrac{105}{100}\right)^2 = x\cdot \dfrac{11025}{10000}[/tex]

Since 11025/10000 = 110.25%, there was an increment of 10.25%

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