Answer:
Current, I = 1.08 A
Explanation:
Given that,
Length of the copper wire, l = 12 cm = 0.12 m
Mass of the wire, m = 16 g = 0.016 kg
Magnetic field, B = 1.2 T
The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.
Magnetic force, F = BIL
Force of gravity, F' = mg
F' = F
[tex]BIL=mg[/tex]
[tex]I=\dfrac{mg}{BL}[/tex]
[tex]I=\dfrac{0.016\times 9.8}{1.2\times 0.12}[/tex]
I = 1.08 A
So, the current through the wire is 1.08 A. Hence, this is the required solution.
