Respuesta :

WojtekR

[tex]x^{13}-2x^{12}-x^{11}+2x^{10}=0\\\\x^{10}\cdot\Big[x^3-2x^2-x+2\Big]=0\\\\x^{10}\cdot\Big[x^2\cdot(x-2)-(x-2)\Big]=0\\\\x^{10}(x-2)(x^2-1)=0\\\\\boxed{x^{10}(x-2)(x+1)(x-1)=0}[/tex]

So:

x = 0 with multiplicity 10 or

x = 2 or

x = 1 or

x = -1

Answer D)

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