Answer:
[tex](x+5)[/tex]
Step-by-step explanation:
[tex]2x^3+13x^2+19x+20[/tex]
[tex]\frac{2x^3+13x^2+19x+20}{x+5}[/tex]
[tex]2x^2+\frac{3x^2+19x+20}{x+5}[/tex]
[tex]2x^2+3x+\frac{4x+20}{x+5}[/tex]
[tex]2x^2+3x+\frac{4x+20}{x+5}[/tex]
[tex]2x^2+3x+4[/tex]
Now we got.
[tex]\left(x+5\right)\left(2x^2+3x+4\right)[/tex]
[tex]\left(x+5\right)[/tex]
