Answer:
FeO.
Explanation:
Firstly, we need to calculate the no. of moles of Fe and O in the sample:
No. of moles of Fe = mass/atomic mass = (11.2 g)/(55.845 g/mol) = 0.2 mol.
No. of moles of O = mass/atomic mass = (3.2 g)/(16.0 g/mol) = 0.2 mol.
Fe and O have the same no. of moles:
∴ The mole ratio of Fe: O is (1: 1).
∴ The empirical formula of the oxide is: FeO.
