Answer:
see explanation
Step-by-step explanation:
For the right triangle
sinx = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{4\sqrt{5} }{12}[/tex] = [tex]\frac{\sqrt{5} }{3}[/tex]
cosx = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{8}{12}[/tex] = [tex]\frac{2}{3}[/tex]
tanx = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{4\sqrt{5} }{8}[/tex] = [tex]\frac{\sqrt{5} }{2}[/tex]
