Respuesta :


[tex]4(px + 1) = 64 \\ 4px + 4 = 64 \\ 4px = 60 \\ px = 15 \\ x = \frac{15}{p} [/tex]
gmany

[tex]4(px+1)=64\qquad|\text{divide both sides by 4}\\\\px+1=16\qquad|\text{subtract 1 from both sides}\\\\px=15\qquad|\text{divide both sides by}\ p\neq0\\\\\boxed{x=\dfrac{15}{p}}[/tex]