For #10
x=2 w(x)= 5
x=0 w(x)=-9
x=1 w(x)=-1
x=4 w(x)=7
To get these answers, you must use the p(x) table. When x=2, p(x)=6. So you would substitute p(x) for 6 and solve. That would be what you would do for the rest of teh problems.
For #12, the answer would be 5x^2+15x+5
Just mutiply the areas of the out side and inside and subtract them
