m= 89/11
[tex] \frac{89}{9} \times \frac{9}{11} = \frac{89}{11} [/tex]
first you turn both fractions into an improper one
[tex] \frac{89}{9} \frac{11}{9} [/tex]
then the second fraction find the recipicol
[tex] \frac{11}{9} ..... \frac{9}{11} [/tex]
the use cross cancel turn the two 9s into a one
[tex] \frac{89}{9} \times \frac{9}{11} [/tex]
