samsix984
samsix984 samsix984
  • 06-10-2018
  • Mathematics
contestada

show that the equation 3sinxtanx = 8 can be written as 3cox^2x + 8cosx - 3

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jimrgrant1 jimrgrant1
  • 06-10-2018

using the trigonometric identities

tanx = [tex]\frac{sinx}{cosx}[/tex] and sin²x = 1 - cos²x

3sinxtanx = 8

( 3sin²x)/ cosx = 8 ( multiply both sides by cosx )

3( 1 - cos²x ) = 8cosx

3 - 3cos² = 8cosx ( subtract 3 - 3cos²x from both sides )

0 = 3cos²x + 8cosx - 3




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