[tex]\bf 49:21\implies \cfrac{49}{21}\implies \cfrac{7\cdot 7}{3\cdot 7}\implies \cfrac{7}{3}\cdot \cfrac{7}{7}\implies \cfrac{7}{3}\cdot 1\implies \cfrac{7}{3}\implies 7:3[/tex]
7 over 3 . Because you find the LCD for both numbers which is 7 and what you do to the top you do to the bottom . 49 divided by 7 is 7 and 21 divided by 7 is 3 and you cant simplify that any lower so the answer is 7 over 3
