we have given the expression [tex] v(t)=20000(0.86)^t [/tex].
we need to find the cost of car initially and after 13 years.
we know that at initially t will be 0.
so [tex] v(0)=20000(0.86)^0=20000 [/tex].
so initially the cost of car is 20000.
when t=13[tex] v(13)=20000(0.86)^(13)=2815.20 [/tex].
so we have plugged corresponding time and found the cost by using the given equation.
