We are given
[tex] 2xy+8y-8x-32 [/tex]
We can write it as
[tex] =2y*x+2y*4-8*x-8*4 [/tex]
we can see that 2y is in first two terms
and -8 is in last two terms
so, we can factor it out
[tex] =2y(x+4)-8(x+4) [/tex]
now, we can see that x+4 is common in both terms
so, we can factor it out
[tex] =(x+4)(2y-8) [/tex]
we can see that
x+4 is one of factor of terms
so, option-B..........Answer
