Answer: -
60 mL of potassium chloride 20% should be diluted to prepare 480 ml of potassium chloride 2.5%
Explanation: -
Volume of potassium chloride solution = 480 mL
Percentage of potassium chloride = 2.5%
Amount of Potassium chloride = [tex] \frac{2.5}{100} [/tex] x 480 mL
= 12 mL
Let the required amount be R.
20 % of R = 12 mL.
[tex] \frac{20}{100} [/tex] x R = 12mL
R = 60 mL.
Thus, 60 mL of potassium chloride 20% should be diluted to prepare 480 ml of potassium chloride 2.5%
