The molarity of a solution of CaCl2 is calculated as below
convert mm to g
1mg =0.001 g
what about 33500 mg=? g
33500 x 0.001 =33.5 g
find the moles of CaCl2 = mass/molar mass
=33.5 g/ 111 g/mol =0.3018 moles
molarity =moles/volume
=0.3018/0.352 =0.857 M
