nathandinh58p4gcrj nathandinh58p4gcrj
  • 09-05-2018
  • Mathematics
contestada

Given a mean of 61.2 and a standard deviation of 21.4 what is the z score of the value 90 rounded to the nearest tenth?

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 04-08-2019

Answer:

The z-score of 90 is 1.35

Step-by-step explanation:

The z-score is calculated using the formula:

[tex]z = \frac{x - \mu}{ \sigma} [/tex]

From the question, it was given that the mean is

[tex] \mu = 61.2[/tex]

and the standard deviation is

[tex] \sigma = 21.4[/tex]

and x=90.

We substitute the given values to obtain:

[tex]z = \frac{90 - 61.2}{21.4} [/tex]

[tex]z = \frac{28.8}{21.4} = 1.35[/tex]

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cpione cpione
  • 29-07-2021

Answer:

1.35

Step-by-step explanation:

Answer Link

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